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X^2=42-11X
We move all terms to the left:
X^2-(42-11X)=0
We add all the numbers together, and all the variables
X^2-(-11X+42)=0
We get rid of parentheses
X^2+11X-42=0
a = 1; b = 11; c = -42;
Δ = b2-4ac
Δ = 112-4·1·(-42)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-17}{2*1}=\frac{-28}{2} =-14 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+17}{2*1}=\frac{6}{2} =3 $
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